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Feedback Control

In feedback control, we have some physical system Hp(s)H_p(s)Hp​(s)
 called a plant which we would like to control using a system of our choice Hc(s)H_c(s)Hc​(s)
 in order to follow some reference signal r(t)r(t)r(t)
.
Notice how the output signal is subtracted from a reference signal, and we use the difference (a.k.a the error) to determine what input we pass into the plant. Looking at the overall transfer function of the system, we see that
​Y(s)=(R(s)−Y(s))Hc(s)Hp(s)(1+Hc(s)Hp(s))Y(s)=Hc(s)Hp(s)R(s)H(s)=Y(s)R(s)=Hc(s)Hp(s)1+Hc(s)Hp(s)\begin{aligned} Y(s) &= (R(s)-Y(s))H_c(s)H_p(s)\\ (1+H_c(s)H_p(s))Y(s) &= H_c(s)H_p(s)R(s)\\ H(s) = \frac{Y(s)}{R(s)} &= \frac{H_c(s)H_p(s)}{1+H_c(s)H_p(s)}\end{aligned}Y(s)(1+Hc​(s)Hp​(s))Y(s)H(s)=R(s)Y(s)​​=(R(s)−Y(s))Hc​(s)Hp​(s)=Hc​(s)Hp​(s)R(s)=1+Hc​(s)Hp​(s)Hc​(s)Hp​(s)​​
​
Depending on what control we use for Hc(s)H_c(s)Hc​(s)
, we can shape this transfer function to be what we want.
Types of Control
Constant Gain Control
When Hc(s)=K0H_c(s) = K_0Hc​(s)=K0​
, this is known as constant gain control.
​H(s)=K0Hp(s)1+K0Hp(s)H(s) = \frac{K_0H_p(s)}{1+K_0H_p(s)}H(s)=1+K0​Hp​(s)K0​Hp​(s)​
​
The poles of this system are clearly when 1+K0Hp(s)=01+K_0H_p(s)=01+K0​Hp​(s)=0
.
Lead Control
Lead controllers are of the form
​Hc(s)=K0s−βs−αH_c(s) = K_0\frac{s-\beta}{s-\alpha}Hc​(s)=K0​s−αs−β​
​
Their poles are when
​1+K0s−βs−αHp(s)=01 + K_0\frac{s-\beta}{s-\alpha}H_p(s) = 01+K0​s−αs−β​Hp​(s)=0
​
Integral Control
Integral controller are of the form
​Hc(s)=K0sH_c(s) = \frac{K_0}{s}Hc​(s)=sK0​​
​
Their poles are when
​1+K0sHp(s)=01 + \frac{K_0}{s}H_p(s) = 01+sK0​​Hp​(s)=0
​
Root Locus Analysis
For all forms of control, we need to choose a constant which places our poles where we want. Root Locus Analysis is the technique which helps us determine how our poles will move as K0→∞K_0\rightarrow \inftyK0​→∞
. Assuming we only have a single gain to choose, we the poles of the new transfer function will be the roots of
​1+K0H(s)1 + K_0H(s)1+K0​H(s)
​
where H(s)H(s)H(s)
 is some transfer function that results in the denominator (For example, in constant gain control, H(s)=Hp(s)H(s) = H_p(s)H(s)=Hp​(s)
 but for lead control, Hs=s−βs−αHp(s)H_s = \frac{s-\beta}{s-\alpha}H_p(s)Hs​=s−αs−β​Hp​(s)
).
Definition 39
The root locus is the set of all points s0∈Cs_0\in \mathbb{C}s0​∈C
 such that ∃K0>0\exists K_0>0∃K0​>0
 such that 1+K0H(s)=01+K_0H(s)=01+K0​H(s)=0
.
This definition implies that H(s0)=1K0H(s_0)=\frac{1}{K_0}H(s0​)=K0​1​
 for some K0K_0K0​
, meaning the root locus is all points such that ∠H(s0)=−180\angle H(s_0)=-180∠H(s0​)=−180
˚. The first step of RLA is to factor the numerator and denominator of H(s)H(s)H(s)
​
​H(s)=∏i=0m(s−βi)∏i=0n(s−αi)H(s) = \frac{\prod_{i=0}^{m}{(s-\beta_i)}}{\prod_{i=0}^{n}{(s-\alpha_i)}}H(s)=∏i=0n​(s−αi​)∏i=0m​(s−βi​)​
​
As k→0,H(s0)=−1K0→∞k\rightarrow 0, H(s_0)=-\frac{1}{K_0}\rightarrow \inftyk→0,H(s0​)=−K0​1​→∞
, so the root locus begins at the poles. As k→∞,H(s0)=−1K0→0k\rightarrow \infty, H(s_0)=-\frac{1}{K_0}\rightarrow 0k→∞,H(s0​)=−K0​1​→0
, so the root locus will end at the open loop zeros. However, if m<nm < nm<n
, (i.e there are more poles than 0’s), not all of the poles can converge to a zero. Instead n−mn-mn−m
 branches will approach ∞\infty∞
 witth asymptotes at
​∑inαi−∑imβin−m\frac{\sum_i^n\alpha_i-\sum_i^m\beta_i}{n-m}n−m∑in​αi​−∑im​βi​​
​
and angles of
​180+(i−1)∗360n−m\frac{180 + (i-1)*360}{n-m}n−m180+(i−1)∗360​
​
The final rule of RLA is that parts of the real line left of an odd number of real poles and zeros are on the root locus. RLA tells us that we have to be careful when choosing our gain K0K_0K0​
 because we could by mistake cause instability. In particular, high gain will cause instability if
​H(s)H(s)H(s)
 has zeros in the right half of the plane
if n−m≥3n-m \ge 3n−m≥3
, then the asympototes will cross the imaginary axis.
Feedback Controller Design
When we design systems to use in feedback control, there are certain properties we want besides just basic ones like stability. Because signals can be thought of as a series of step signals, when analyzing these properties, we will assume r(t)=u(t)r(t)=u(t)r(t)=u(t)
​
Steady State Tracking Accuracy
Definition 40
A system has steady state tracking accurracy if the different between the reference and the output signals tends to 0 as t→∞t\rightarrow \inftyt→∞
​
​ess:=lim⁡t→∞e(t)=0e_{ss} := \lim_{t\rightarrow\infty}{e(t)}=0ess​:=limt→∞​e(t)=0
​
A useful theorem which can help us evaluate this limit is the final value theorem.
Theorem 17 (Final Value Theorem)
​lim⁡t→∞e(t)=lim⁡s→0sE(s)\lim_{t\rightarrow\infty}{e(t)} = \lim_{s\rightarrow0}{sE(s)}limt→∞​e(t)=lims→0​sE(s)
​
As long as a limit exists and e(t)=0e(t)=0e(t)=0
 for t<0t<0t<0
​
Looking at the relationship between E(s)E(s)E(s)
 and R(s)R(s)R(s)
, we see that
​E(s)R(s)=11+Hc(s)Hp(s)  ⟹  E(s)=1s1+Hc(s)Hp(s)\frac{E(s)}{R(s)} = \frac{1}{1+H_c(s)H_p(s)} \implies E(s) = \frac{\frac{1}{s}}{1+H_c(s)H_p(s)}R(s)E(s)​=1+Hc​(s)Hp​(s)1​⟹E(s)=1+Hc​(s)Hp​(s)s1​​
​
Thus
​ess=lim⁡s→011+Hc(s)Hp(s)e_{ss}=\lim_{s\rightarrow0}{\frac{1}{1+H_c(s)H_p(s)}}ess​=lims→0​1+Hc​(s)Hp​(s)1​
​
Thus as long as Hc(s)Hp(s)H_c(s)H_p(s)Hc​(s)Hp​(s)
 has at least one pole at s=0s=0s=0
, then ess=0e_{ss}=0ess​=0
. Notice that integral control gives us a pole at s0s_0s0​
, so it is guaranteed that an integral controller will be steady-state accurate.
Disturbance Rejection
Sometimes the output of our controller can be disturbed before it goes into the plant. Ideally, our system should be robust to these disturbances.
​Y(s)=Hp(s)[Hc(s)(Rs−Ys)+D(s)]Y(s)=Hc(s)Hp(s)1+Hc(s)Hp(s)R(s)+Hp(s)1+Hc(s)Hp(s)D(s)\begin{aligned} Y(s) &= H_p(s)\left[H_c(s)(R_s-Y_s)+D(s)\right]\\ Y(s) &= \frac{H_c(s)H_p(s)}{1+H_c(s)H_p(s)}R(s) + \frac{H_p(s)}{1+H_c(s)H_p(s)}D(s)\end{aligned}Y(s)Y(s)​=Hp​(s)[Hc​(s)(Rs​−Ys​)+D(s)]=1+Hc​(s)Hp​(s)Hc​(s)Hp​(s)​R(s)+1+Hc​(s)Hp​(s)Hp​(s)​D(s)​
​
The system will reject disturbances if the Hp(s)1+Hc(s)Hp(s)D(s)\frac{H_p(s)}{1+H_c(s)H_p(s)}D(s)1+Hc​(s)Hp​(s)Hp​(s)​D(s)
 is close to 000
 in the steady state. Assuming that d(t)=u(t)d(t) = u(t)d(t)=u(t)
, we see that
​δss=lim⁡s→0sHp(s)1+Hc(s)Hp(s)1s=lim⁡s→0Hp(s)1+Hc(s)Hp(s)\delta_{ss} = \lim_{s\rightarrow0}{s\frac{H_p(s)}{1+H_c(s)H_p(s)}\frac{1}{s}}=\lim_{s\rightarrow0}{\frac{H_p(s)}{1+H_c(s)H_p(s)}}δss​=lims→0​s1+Hc​(s)Hp​(s)Hp​(s)​s1​=lims→0​1+Hc​(s)Hp​(s)Hp​(s)​
​
Thus as long as HcH_cHc​
 has a pole at 000
, then the system will reject disturbances. Notice that integral control guarantees disturbance rejection as well.
Noise Insensitivity
In real systems, our measurement of the output y(t)y(t)y(t)
 is not always 100% accurate. One way to model this is to add a noise term to the output. Looking at the relationship between the noise and the output signal, we see
​H(s)=−Hc(s)Hp(s)1+Hc(s)Hp(s)H(s) = \frac{-H_c(s)H_p(s)}{1+H_c(s)H_p(s)}H(s)=1+Hc​(s)Hp​(s)−Hc​(s)Hp​(s)​
​
In order to reject this noise, we want this term to be close to 0, so ideally Hc(s)Hp(s)<<1H_c(s)H_p(s) << 1Hc​(s)Hp​(s)<<1
 as s→0s\rightarrow 0s→0
. However, this conflicts with our desire for Hc(s)Hp(s)H_c(s)H_p(s)Hc​(s)Hp​(s)
 to have a pole at 0 to guarantee steady state tracking. Thus it is difficult to make a controler that is both accurate and robust to noise. However, because noise is usually a high frequency signal and the reference is a low frequency signal, we can mitigate this by choosing Hc(s)Hp(s)H_c(s)H_p(s)Hc​(s)Hp​(s)
 to be a low-pass filter.
Linear Time-Invariant Systems
Sampling
Last modified 2yr ago