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Feedback Control

In feedback control, we have some physical system
called a plant which we would like to control using a system of our choice
in order to follow some reference signal
Notice how the output signal is subtracted from a reference signal, and we use the difference (a.k.a the error) to determine what input we pass into the plant. Looking at the overall transfer function of the system, we see that
Y(s)=(R(s)Y(s))Hc(s)Hp(s)(1+Hc(s)Hp(s))Y(s)=Hc(s)Hp(s)R(s)H(s)=Y(s)R(s)=Hc(s)Hp(s)1+Hc(s)Hp(s)\begin{aligned} Y(s) &= (R(s)-Y(s))H_c(s)H_p(s)\\ (1+H_c(s)H_p(s))Y(s) &= H_c(s)H_p(s)R(s)\\ H(s) = \frac{Y(s)}{R(s)} &= \frac{H_c(s)H_p(s)}{1+H_c(s)H_p(s)}\end{aligned}
Depending on what control we use for
, we can shape this transfer function to be what we want.

Types of Control

Constant Gain Control

Hc(s)=K0H_c(s) = K_0
, this is known as constant gain control.
H(s)=K0Hp(s)1+K0Hp(s)H(s) = \frac{K_0H_p(s)}{1+K_0H_p(s)}
The poles of this system are clearly when

Lead Control

Lead controllers are of the form
Hc(s)=K0sβsαH_c(s) = K_0\frac{s-\beta}{s-\alpha}
Their poles are when
1+K0sβsαHp(s)=01 + K_0\frac{s-\beta}{s-\alpha}H_p(s) = 0

Integral Control

Integral controller are of the form
Hc(s)=K0sH_c(s) = \frac{K_0}{s}
Their poles are when
1+K0sHp(s)=01 + \frac{K_0}{s}H_p(s) = 0

Root Locus Analysis

For all forms of control, we need to choose a constant which places our poles where we want. Root Locus Analysis is the technique which helps us determine how our poles will move as
K0K_0\rightarrow \infty
. Assuming we only have a single gain to choose, we the poles of the new transfer function will be the roots of
1+K0H(s)1 + K_0H(s)
is some transfer function that results in the denominator (For example, in constant gain control,
H(s)=Hp(s)H(s) = H_p(s)
but for lead control,
Hs=sβsαHp(s)H_s = \frac{s-\beta}{s-\alpha}H_p(s)

Definition 39

The root locus is the set of all points
s0Cs_0\in \mathbb{C}
such that
K0>0\exists K_0>0
such that
This definition implies that
for some
, meaning the root locus is all points such that
H(s0)=180\angle H(s_0)=-180
˚. The first step of RLA is to factor the numerator and denominator of
H(s)=i=0m(sβi)i=0n(sαi)H(s) = \frac{\prod_{i=0}^{m}{(s-\beta_i)}}{\prod_{i=0}^{n}{(s-\alpha_i)}}
k0,H(s0)=1K0k\rightarrow 0, H(s_0)=-\frac{1}{K_0}\rightarrow \infty
, so the root locus begins at the poles. As
k,H(s0)=1K00k\rightarrow \infty, H(s_0)=-\frac{1}{K_0}\rightarrow 0
, so the root locus will end at the open loop zeros. However, if
m<nm < n
, (i.e there are more poles than 0’s), not all of the poles can converge to a zero. Instead
branches will approach
witth asymptotes at
and angles of
180+(i1)360nm\frac{180 + (i-1)*360}{n-m}
The final rule of RLA is that parts of the real line left of an odd number of real poles and zeros are on the root locus. RLA tells us that we have to be careful when choosing our gain
because we could by mistake cause instability. In particular, high gain will cause instability if
  • H(s)H(s)
    has zeros in the right half of the plane
  • if
    nm3n-m \ge 3
    , then the asympototes will cross the imaginary axis.

Feedback Controller Design

When we design systems to use in feedback control, there are certain properties we want besides just basic ones like stability. Because signals can be thought of as a series of step signals, when analyzing these properties, we will assume

Steady State Tracking Accuracy

Definition 40

A system has steady state tracking accurracy if the different between the reference and the output signals tends to 0 as
tt\rightarrow \infty
ess:=limte(t)=0e_{ss} := \lim_{t\rightarrow\infty}{e(t)}=0
A useful theorem which can help us evaluate this limit is the final value theorem.

Theorem 17 (Final Value Theorem)

limte(t)=lims0sE(s)\lim_{t\rightarrow\infty}{e(t)} = \lim_{s\rightarrow0}{sE(s)}
As long as a limit exists and
Looking at the relationship between
, we see that
E(s)R(s)=11+Hc(s)Hp(s)    E(s)=1s1+Hc(s)Hp(s)\frac{E(s)}{R(s)} = \frac{1}{1+H_c(s)H_p(s)} \implies E(s) = \frac{\frac{1}{s}}{1+H_c(s)H_p(s)}
Thus as long as
has at least one pole at
, then
. Notice that integral control gives us a pole at
, so it is guaranteed that an integral controller will be steady-state accurate.

Disturbance Rejection

Sometimes the output of our controller can be disturbed before it goes into the plant. Ideally, our system should be robust to these disturbances.
Y(s)=Hp(s)[Hc(s)(RsYs)+D(s)]Y(s)=Hc(s)Hp(s)1+Hc(s)Hp(s)R(s)+Hp(s)1+Hc(s)Hp(s)D(s)\begin{aligned} Y(s) &= H_p(s)\left[H_c(s)(R_s-Y_s)+D(s)\right]\\ Y(s) &= \frac{H_c(s)H_p(s)}{1+H_c(s)H_p(s)}R(s) + \frac{H_p(s)}{1+H_c(s)H_p(s)}D(s)\end{aligned}
The system will reject disturbances if the
is close to
in the steady state. Assuming that
d(t)=u(t)d(t) = u(t)
, we see that
δss=lims0sHp(s)1+Hc(s)Hp(s)1s=lims0Hp(s)1+Hc(s)Hp(s)\delta_{ss} = \lim_{s\rightarrow0}{s\frac{H_p(s)}{1+H_c(s)H_p(s)}\frac{1}{s}}=\lim_{s\rightarrow0}{\frac{H_p(s)}{1+H_c(s)H_p(s)}}
Thus as long as
has a pole at
, then the system will reject disturbances. Notice that integral control guarantees disturbance rejection as well.

Noise Insensitivity

In real systems, our measurement of the output
is not always 100% accurate. One way to model this is to add a noise term to the output. Looking at the relationship between the noise and the output signal, we see
H(s)=Hc(s)Hp(s)1+Hc(s)Hp(s)H(s) = \frac{-H_c(s)H_p(s)}{1+H_c(s)H_p(s)}
In order to reject this noise, we want this term to be close to 0, so ideally
Hc(s)Hp(s)<<1H_c(s)H_p(s) << 1
s0s\rightarrow 0
. However, this conflicts with our desire for
to have a pole at 0 to guarantee steady state tracking. Thus it is difficult to make a controler that is both accurate and robust to noise. However, because noise is usually a high frequency signal and the reference is a low frequency signal, we can mitigate this by choosing
to be a low-pass filter.